Project Euler Lab - Problem 168

#168 - Number Rotations

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Consider the number \(142857\). We can right-rotate this number by moving the last digit (\(7\)) to the front of it, giving us \(714285\).
It can be verified that \(714285 = 5 \times 142857\).
This demonstrates an unusual property of \(142857\): it is a divisor of its right-rotation.

Find the last \(5\) digits of the sum of all integers \(n\), \(10 \lt n \lt 10^{100}\), that have this property.

This problem is taken from Project Euler, Problem 168.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=168. Published Friday, 16th November 2007, 05:00 pm. Solved by 3,144 members at time of mirroring.

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