Project Euler Lab - Problem 231

#231 - Prime Factorisation of Binomial Coefficients

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The binomial coefficient \(\displaystyle \binom {10} 3 = 120\).
\(120 = 2^3 \times 3 \times 5 = 2 \times 2 \times 2 \times 3 \times 5\), and \(2 + 2 + 2 + 3 + 5 = 14\).
So the sum of the terms in the prime factorisation of \(\displaystyle \binom {10} 3\) is \(14\).

Find the sum of the terms in the prime factorisation of \(\displaystyle \binom {20\,000\,000} {15\,000\,000}\).

This problem is taken from Project Euler, Problem 231.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=231. Published Friday, 6th February 2009, 01:00 pm. Solved by 6,212 members at time of mirroring.

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Mathematical Foundation. Exact counting underlies discrete pricing lattices, scenario enumeration, and combinatorial probability (Phase 7).

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