Project Euler Lab - Problem 265

#265 - Binary Circles

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\(2^N\) binary digits can be placed in a circle so that all the \(N\)-digit clockwise subsequences are distinct.

For \(N=3\), two such circular arrangements are possible, ignoring rotations:

0265_BinaryCircles.gif

For the first arrangement, the \(3\)-digit subsequences, in clockwise order, are:
\(000\), \(001\), \(010\), \(101\), \(011\), \(111\), \(110\) and \(100\).

Each circular arrangement can be encoded as a number by concatenating the binary digits starting with the subsequence of all zeros as the most significant bits and proceeding clockwise. The two arrangements for \(N=3\) are thus represented as \(23\) and \(29\):

\[\begin{align} 00010111_2 &= 23\\ 00011101_2 &= 29 \end{align}\]

Calling \(S(N)\) the sum of the unique numeric representations, we can see that \(S(3) = 23 + 29 = 52\).

Find \(S(5)\).

This problem is taken from Project Euler, Problem 265.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=265. Published Saturday, 21st November 2009, 09:00 am. Solved by 4,748 members at time of mirroring.

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