Project Euler Lab - Problem 274

#274 - Divisibility Multipliers

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For each integer \(p \gt 1\) coprime to \(10\) there is a positive divisibility multiplier \(m \lt p\) which preserves divisibility by \(p\) for the following function on any positive integer, \(n\):

\(f(n) = (\text{all but the last digit of }n) + (\text{the last digit of }n) \cdot m\).

That is, if \(m\) is the divisibility multiplier for \(p\), then \(f(n)\) is divisible by \(p\) if and only if \(n\) is divisible by \(p\).

(When \(n\) is much larger than \(p\), \(f(n)\) will be less than \(n\) and repeated application of \(f\) provides a multiplicative divisibility test for \(p\).)

For example, the divisibility multiplier for \(113\) is \(34\).

\(f(76275) = 7627 + 5 \cdot 34 = 7797\): \(76275\) and \(7797\) are both divisible by \(113\).
\(f(12345) = 1234 + 5 \cdot 34 = 1404\): \(12345\) and \(1404\) are both not divisible by \(113\).

The sum of the divisibility multipliers for the primes that are coprime to \(10\) and less than \(1000\) is \(39517\). What is the sum of the divisibility multipliers for the primes that are coprime to \(10\) and less than \(10^7\)?

This problem is taken from Project Euler, Problem 274.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=274. Published Friday, 15th January 2010, 01:00 pm. Solved by 1,694 members at time of mirroring.

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