Project Euler Lab - Problem 277

#277 - A Modified Collatz Sequence

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A modified Collatz sequence of integers is obtained from a starting value \(a_1\) in the following way:

\(a_{n+1} = \, \,\, \frac {a_n} 3 \quad\) if \(a_n\) is divisible by \(3\). We shall denote this as a large downward step, "D".

\(a_{n+1} = \frac {4 a_n+2} 3 \, \,\) if \(a_n\) divided by \(3\) gives a remainder of \(1\). We shall denote this as an upward step, "U".

\(a_{n+1} = \frac {2 a_n -1} 3 \, \,\) if \(a_n\) divided by \(3\) gives a remainder of \(2\). We shall denote this as a small downward step, "d".

The sequence terminates when some \(a_n = 1\).

Given any integer, we can list out the sequence of steps.
For instance if \(a_1=231\), then the sequence \(\{a_n\}=\{231,77,51,17,11,7,10,14,9,3,1\}\) corresponds to the steps "DdDddUUdDD".

Of course, there are other sequences that begin with that same sequence "DdDddUUdDD....".
For instance, if \(a_1=1004064\), then the sequence is DdDddUUdDDDdUDUUUdDdUUDDDUdDD.
In fact, \(1004064\) is the smallest possible \(a_1 > 10^6\) that begins with the sequence DdDddUUdDD.

What is the smallest \(a_1 > 10^{15}\) that begins with the sequence "UDDDUdddDDUDDddDdDddDDUDDdUUDd"?

This problem is taken from Project Euler, Problem 277.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=277. Published Saturday, 6th February 2010, 01:00 am. Solved by 3,727 members at time of mirroring.

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