Project Euler Lab - Problem 331

#331 - Cross Flips

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\(N \times N\) disks are placed on a square game board. Each disk has a black side and white side.

At each turn, you may choose a disk and flip all the disks in the same row and the same column as this disk: thus \(2 \times N - 1\) disks are flipped. The game ends when all disks show their white side. The following example shows a game on a \(5 \times 5\) board.

0331_crossflips3.gif

It can be proven that \(3\) is the minimal number of turns to finish this game.

The bottom left disk on the \(N \times N\) board has coordinates \((0,0)\);
the bottom right disk has coordinates \((N-1,0)\) and the top left disk has coordinates \((0,N-1)\).

Let \(C_N\) be the following configuration of a board with \(N \times N\) disks:
A disk at \((x, y)\) satisfying \(N - 1 \le \sqrt{x^2 + y^2} \lt N\), shows its black side; otherwise, it shows its white side. \(C_5\) is shown above.

Let \(T(N)\) be the minimal number of turns to finish a game starting from configuration \(C_N\) or \(0\) if configuration \(C_N\) is unsolvable.
We have shown that \(T(5)=3\). You are also given that \(T(10)=29\) and \(T(1\,000)=395253\).

Find \(\sum \limits_{i = 3}^{31} T(2^i - i)\).

This problem is taken from Project Euler, Problem 331.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=331. Published Sunday, 3rd April 2011, 08:00 am. Solved by 523 members at time of mirroring.

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