Project Euler Lab - Problem 417

#417 - Reciprocal Cycles II

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A unit fraction contains \(1\) in the numerator. The decimal representation of the unit fractions with denominators \(2\) to \(10\) are given:

\[\begin{align} 1/2 &= 0.5\\ 1/3 &=0.(3)\\ 1/4 &=0.25\\ 1/5 &= 0.2\\ 1/6 &= 0.1(6)\\ 1/7 &= 0.(142857)\\ 1/8 &= 0.125\\ 1/9 &= 0.(1)\\ 1/10 &= 0.1 \end{align}\]

Where \(0.1(6)\) means \(0.166666\cdots\), and has a \(1\)-digit recurring cycle. It can be seen that \(1/7\) has a \(6\)-digit recurring cycle.

Unit fractions whose denominator has no other prime factors than \(2\) and/or \(5\) are not considered to have a recurring cycle.
We define the length of the recurring cycle of those unit fractions as \(0\).

Let \(L(n)\) denote the length of the recurring cycle of \(1/n\). You are given that \(\sum L(n)\) for \(3 \leq n \leq 1\,000\,000\) equals \(55535191115\).

Find \(\sum L(n)\) for \(3 \leq n \leq 100\,000\,000\).

This problem is taken from Project Euler, Problem 417.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=417. Published Saturday, 2nd March 2013, 04:00 pm. Solved by 1,082 members at time of mirroring.

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