Project Euler Lab - Problem 422

#422 - Sequence of Points on a Hyperbola

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Let \(H\) be the hyperbola defined by the equation \(12x^2 + 7xy - 12y^2 = 625\).

Next, define \(X\) as the point \((7, 1)\). It can be seen that \(X\) is in \(H\).

Now we define a sequence of points in \(H\), \(\{P_i: i \geq 1\}\), as:

  • \(P_1 = (13, 61/4)\).
  • \(P_2 = (-43/6, -4)\).
  • For \(i \gt 2\), \(P_i\) is the unique point in \(H\) that is different from \(P_{i-1}\) and such that line \(P_iP_{i-1}\) is parallel to line \(P_{i-2}X\). It can be shown that \(P_i\) is well-defined, and that its coordinates are always rational.
0422_hyperbola.gif

You are given that \(P_3 = (-19/2, -229/24)\), \(P_4 = (1267/144, -37/12)\) and \(P_7 = (17194218091/143327232, 274748766781/1719926784)\).

Find \(P_n\) for \(n = 11^{14}\) in the following format:
If \(P_n = (a/b, c/d)\) where the fractions are in lowest terms and the denominators are positive, then the answer is \((a + b + c + d) \bmod 1\,000\,000\,007\).

For \(n = 7\), the answer would have been: \(806236837\).

This problem is taken from Project Euler, Problem 422.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=422. Published Sunday, 7th April 2013, 07:00 am. Solved by 342 members at time of mirroring.

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