Project Euler Lab - Problem 465

#465 - Polar Polygons

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The kernel of a polygon is defined by the set of points from which the entire polygon's boundary is visible. We define a polar polygon as a polygon for which the origin is strictly contained inside its kernel.

For this problem, a polygon can have collinear consecutive vertices. However, a polygon still cannot have self-intersection and cannot have zero area.

For example, only the first of the following is a polar polygon (the kernels of the second, third, and fourth do not strictly contain the origin, and the fifth does not have a kernel at all):

0465_polygons.png

Notice that the first polygon has three consecutive collinear vertices.

Let \(P(n)\) be the number of polar polygons such that the vertices \((x, y)\) have integer coordinates whose absolute values are not greater than \(n\).

Note that polygons should be counted as different if they have different set of edges, even if they enclose the same area. For example, the polygon with vertices \([(0,0),(0,3),(1,1),(3,0)]\) is distinct from the polygon with vertices \([(0,0),(0,3),(1,1),(3,0),(1,0)]\).

For example, \(P(1) = 131\), \(P(2) = 1648531\), \(P(3) = 1099461296175\) and \(P(343) \bmod 1\,000\,000\,007 = 937293740\).

Find \(P(7^{13}) \bmod 1\,000\,000\,007\).

This problem is taken from Project Euler, Problem 465.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=465. Published Sunday, 30th March 2014, 05:00 am. Solved by 275 members at time of mirroring.

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Algorithmic Development. Optimal substructure and state-space reasoning are exactly how American-option pricing and optimal execution are solved (Phases 13, 16).

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