Project Euler Lab - Problem 564

#564 - Maximal Polygons

● ResearchOfficial difficulty: 73%PointsTier C - reduced scale in browser; full scale in notebookNot viewed
↖ Euler Lab

A line segment of length \(2n-3\) is randomly split into \(n\) segments of integer length (\(n \ge 3\)). In the sequence given by this split, the segments are then used as consecutive sides of a convex \(n\)-polygon, formed in such a way that its area is maximal. All of the \(\binom{2n-4} {n-1}\) possibilities for splitting up the initial line segment occur with the same probability.

Let \(E(n)\) be the expected value of the area that is obtained by this procedure.
For example, for \(n=3\) the only possible split of the line segment of length \(3\) results in three line segments with length \(1\), that form an equilateral triangle with an area of \(\frac 1 4 \sqrt{3}\). Therefore \(E(3)=0.433013\), rounded to \(6\) decimal places.
For \(n=4\) you can find \(4\) different possible splits, each of which is composed of three line segments with length \(1\) and one line segment with length \(2\). All of these splits lead to the same maximal quadrilateral with an area of \(\frac 3 4 \sqrt{3}\), thus \(E(4)=1.299038\), rounded to \(6\) decimal places.

Let \(S(k)=\displaystyle \sum_{n=3}^k E(n)\).
For example, \(S(3)=0.433013\), \(S(4)=1.732051\), \(S(5)=4.604767\) and \(S(10)=66.955511\), rounded to \(6\) decimal places each.

Find \(S(50)\), rounded to \(6\) decimal places.

This problem is taken from Project Euler, Problem 564.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=564. Published Sunday, 12th June 2016, 07:00 am. Solved by 288 members at time of mirroring.

Why this is useful

Probability Statistics. Expectation and state-based probability reasoning underpin pricing, risk, and statistical inference (Phases 7, 11, 13).

We classify relevance honestly - not every Euler problem is a trading application.

Learning mode

Pick how much scaffolding you want. Your choice is remembered per problem.

Scratchpad

Mathematical notes, formulas, pseudocode, hypotheses, complexity notes. Saved automatically with your progress.

Python workbench

Tier C - reduced scale in browser; full scale in notebook
Browser runs a reduced, clearly-labelled educational scale; the original scale is provided in a local notebook.

Real Python (Pyodide) in a sandboxed Web Worker - no network, no filesystem, no DOM access. Ctrl/Cmd+Enter runs. Escape leaves the editor. Stop terminates the worker.

Python runtime not loaded (it boots on first run - a one-time local load).

Check your answer

Answers are checked against a salted hash held in a separate file - not printed in this page. This prevents accidental spoilers; it is not cryptographic protection (see the build notes).

Progressive hints

Confidence

Low confidence schedules this problem for spaced review, even if you solved it.

Reference solution

Spoiler
The complete original explanation (interpretation, naive approach, insight, proof, complexity, Python implementation, tests, common mistakes, alternatives) is hidden and lazy-loaded. Reveal it only after a meaningful attempt - the struggle is where the learning happens.