Project Euler Lab - Problem 598

#598 - Split Divisibilities

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Consider the number \(48\).
There are five pairs of integers \(a\) and \(b\) (\(a \leq b\)) such that \(a \times b=48\): \((1,48)\), \((2,24)\), \((3,16)\), \((4,12)\) and \((6,8)\).
It can be seen that both \(6\) and \(8\) have \(4\) divisors.
So of those five pairs one consists of two integers with the same number of divisors.

In general:
Let \(C(n)\) be the number of pairs of positive integers \(a \times b=n\), (\(a \leq b\)) such that \(a\) and \(b\) have the same number of divisors;
so \(C(48)=1\).

You are given \(C(10!)=3\): \((1680, 2160)\), \((1800, 2016)\) and \((1890,1920)\).

Find \(C(100!)\).

This problem is taken from Project Euler, Problem 598.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=598. Published Sunday, 9th April 2017, 10:00 am. Solved by 595 members at time of mirroring.

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