Project Euler Lab - Problem 6

#6 - Sum Square Difference

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The sum of the squares of the first ten natural numbers is,

\[1^2 + 2^2 + ... + 10^2 = 385.\]

The square of the sum of the first ten natural numbers is,

\[(1 + 2 + ... + 10)^2 = 55^2 = 3025.\]

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is \(3025 - 385 = 2640\).

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

This problem is taken from Project Euler, Problem 6.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=6. Published Friday, 14th December 2001, 06:00 pm. Solved by 529,452 members at time of mirroring.

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