Project Euler Lab - Problem 647

#647 - Linear Transformations of Polygonal Numbers

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It is possible to find positive integers \(A\) and \(B\) such that given any triangular number, \(T_n\), then \(AT_n +B\) is always a triangular number. We define \(F_3(N)\) to be the sum of \((A+B)\) over all such possible pairs \((A,B)\) with \(\max(A,B)\le N\). For example \(F_3(100) = 184\).

Polygonal numbers are generalisations of triangular numbers. Polygonal numbers with parameter \(k\) we call \(k\)-gonal numbers. The formula for the \(n\)th \(k\)-gonal number is \(\frac 12n\big(n(k-2)+4-k\big)\) where \(n \ge 1\). For example when \(k = 3\) we get \(\frac 12n(n+1)\) the formula for triangular numbers.

The statement above is true for pentagonal, heptagonal and in fact any \(k\)-gonal number with \(k\) odd. For example when \(k=5\) we get the pentagonal numbers and we can find positive integers \(A\) and \(B\) such that given any pentagonal number, \(P_n\), then \(AP_n+B\) is always a pentagonal number. We define \(F_5(N)\) to be the sum of \((A+B)\) over all such possible pairs \((A,B)\) with \(\max(A,B)\le N\).

Similarly we define \(F_k(N)\) for odd \(k\). You are given \(\sum_{k} F_k(10^3) = 14993\) where the sum is over all odd \(k = 3,5,7,\ldots\).

Find \(\sum_{k} F_k(10^{12})\) where the sum is over all odd \(k = 3,5,7,\ldots\)

This problem is taken from Project Euler, Problem 647.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=647. Published Sunday, 16th December 2018, 07:00 am. Solved by 536 members at time of mirroring.

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