Project Euler Lab - Problem 682

#682 - $5$-Smooth Pairs

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\(5\)-smooth numbers are numbers whose largest prime factor doesn't exceed \(5\).
\(5\)-smooth numbers are also called Hamming numbers.

Let \(\Omega(a)\) be the count of prime factors of \(a\) (counted with multiplicity).
Let \(s(a)\) be the sum of the prime factors of \(a\) (with multiplicity).
For example, \(\Omega(300) = 5\) and \(s(300) = 2+2+3+5+5 = 17\).

Let \(f(n)\) be the number of pairs, \((p,q)\), of Hamming numbers such that \(\Omega(p)=\Omega(q)\) and \(s(p)+s(q)=n\).
You are given \(f(10)=4\) (the pairs are \((4,9),(5,5),(6,6),(9,4)\)) and \(f(10^2)=3629\).

Find \(f(10^7) \bmod 1\,000\,000\,007\).

This problem is taken from Project Euler, Problem 682.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=682. Published Sunday, 6th October 2019, 10:00 am. Solved by 327 members at time of mirroring.

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