#736 - Paths to Equality
Define two functions on lattice points:
A path to equality of length \(n\) for a pair \((a,b)\) is a sequence \(\Big((a_1,b_1),(a_2,b_2),\ldots,(a_n,b_n)\Big)\), where:
- \((a_1,b_1) = (a,b)\)
- \((a_k,b_k) = r(a_{k-1},b_{k-1})\) or \((a_k,b_k) = s(a_{k-1},b_{k-1})\) for \(k > 1\)
- \(a_k \ne b_k\) for \(k < n\)
- \(a_n = b_n\)
\(a_n = b_n\) is called the final value.
For example,
This is a path to equality for \((45,90)\) and is of length 10 with final value 1476. There is no path to equality of \((45,90)\) with smaller length.
Find the unique path to equality for \((45,90)\) with smallest odd length. Enter the final value as your answer.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=736. Published Sunday, 29th November 2020, 01:00 am. Solved by 268 members at time of mirroring.
Why this is useful
Algorithmic Development. Graph/state-space search transfers to routing, dependency resolution, and execution-path optimisation (Phases 16, 17).
We classify relevance honestly - not every Euler problem is a trading application.
Prerequisites
Lessons that prepare you:
17.1 Python for Quants: NumPy, pandas, and Vectorization · 19.14 Computational Complexity, Feasibility Estimation, and Proving Algorithms Correct · 19.9 Graph Algorithms: BFS, DFS, Dijkstra, and Minimum Spanning Trees · 19.6 Recurrence Relations and Generating Functions · 19.10 Search: Backtracking, Branch-and-Bound, Binary Search, Meet-in-the-Middle · 2.7 Sequences, Series, Convergence, and Power Series · 3.1 Vectors, Multivariable Functions, and Level Sets
Recommended stepping-stone problems: #165 · #388 · #496
Concepts: computational-geometry geometry sequences-series brute-force-reduction
Likely techniques: bfs-dfs hashing
Learning mode
Pick how much scaffolding you want. Your choice is remembered per problem.
Understand the problem
- What exactly is the input to problem 736? Is it a bound (45), a supplied dataset, or a definition you must generate from?
- What is the required output - restate it precisely: one extremal object (or the value attached to it), so a search-with-pruning shape is natural.
- Write out, in your own words, the definition of final value as the statement gives it. Which integers/objects are excluded by that definition?
- What do the arguments of r(x,y), s(x,y) mean, and what is the value's type (count, sum, probability)?
- What are the edge cases: the smallest legal object, zero/one, ties, and the boundary at exactly 45?
- Why is brute force hard HERE specifically? Estimate the number of candidates implied by 45 and the cost of testing one.
- Which computational-geometry fact would, if true, collapse the search - and can you state it as a testable claim before you look for a proof?
Predict & plan (before you code)
- Predict the strategy: in one sentence, what will your solution do? (The classification says computational-geometry / bfs-dfs - do you agree, and why?)
- Predict the complexity of your intended method in terms of N = 45, and the wall-clock time you expect. Write both down now.
- Predict the key data structure: what is stored, keyed by what, and how large will it get at full scale?
- Predict the failure mode: what is most likely to break - an off-by-one on the bound, a definition misread, precision, or memory?
- Predict the output of the small case from rung 3 BEFORE running it (the statement says: "For example, (45,90) r (46,180) s(92,181) s(184,182) s(368,183) s(736,184) r (737,368) s(1474,369) r(1475,738) r(1476,1476) This is a path to equality for (45,90) and is of length 10 with final value 1476.") - then run it. A surprise here is worth more than an hour of debugging later.
Scratchpad
Mathematical notes, formulas, pseudocode, hypotheses, complexity notes. Saved automatically with your progress.
Python workbench
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Check your answer
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Progressive hints
Optimization
You have a correct answer. That is the start of the learning, not the end.
- Reduce the time complexity. What is the bottleneck, and what mathematical fact removes it?
- Reduce memory. Can you stream, or keep only the last k states?
- Replace brute force with a closed form, a sieve, a recurrence, or a symmetry argument.
- Prove the optimized version computes the same thing.
- Compare two implementations and time them.
Explain it
Which step of your solution were you least confident about, and what evidence would settle it?
What did you try first, and what specifically made you abandon it - a proof, a timing, or a wrong small-case answer?
Where did the computational-geometry structure do the real work? Name the single observation that collapsed the search space.
Could you have reached the bfs-dfs idea faster? Which words in the statement were pointing at it, and did you notice them?
What was the bug that cost you the most time, and what CLASS of bug was it (off-by-one, definition misread, precision, state under-specified)?
How would your solution change if the bound 45 were multiplied by 1000? Does it survive, or does it need a different idea?
What is the honest complexity of what you wrote (not what you intended), and where is the remaining slack?
Which problem you have already solved is this most similar to, and what is the shared skeleton - is it really 'bfs-dfs' underneath?
State the transferable technique in one sentence, without mentioning this problem's story at all.
Self-assess (mastery is not a correct number)
You reach Mastered only when you have solved it, rated yourself at least Solid across the dimensions, and written a real explanation.
Confidence
Low confidence schedules this problem for spaced review, even if you solved it.
Mastery check
- Variation: change the bound (or a rule) in the statement. Does your method still work? What breaks first?
- Constraints: if the limit were 10× larger, which step fails, and what would you replace it with?
- Related problem: #165 · #388 · #496
- Transfer: where else does this technique appear? Name a lesson and a real computational setting.
- Spaced re-attempt: come back after the review interval and re-solve it with no hints.