Project Euler Lab - Problem 748

#748 - Upside Down Diophantine Equation

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Upside Down is a modification of the famous Pythagorean equation: \[\begin{align} \frac{1}{x^2}+\frac{1}{y^2}=\frac{13}{z^2}. \end{align}\]

A solution \((x,y,z)\) to this equation with \(x,y\) and \(z\) positive integers is a primitive solution if \(\gcd(x,y,z)=1\).

Let \(S(N)\) be the sum of \(x+y+z\) over primitive Upside Down solutions such that \(1 \leq x,y,z \leq N\) and \(x \le y\).
For \(N=100\) the primitive solutions are \((2,3,6)\) and \((5,90,18)\), thus \(S(10^2)=124\).
It can be checked that \(S(10^3)=1470\) and \(S(10^5)=2340084\).

Find \(S(10^{16})\) and give the last \(9\) digits as your answer.

This problem is taken from Project Euler, Problem 748.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=748. Published Saturday, 20th February 2021, 01:00 pm. Solved by 364 members at time of mirroring.

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