Project Euler Lab - Problem 763

#763 - Amoebas in a 3D Grid

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Consider a three dimensional grid of cubes. An amoeba in cube \((x, y, z)\) can divide itself into three amoebas to occupy the cubes \((x + 1, y, z)\), \((x, y + 1, z)\) and \((x, y, z + 1)\), provided these cubes are empty.

Originally there is only one amoeba in the cube \((0, 0, 0)\). After \(N\) divisions there will be \(2N+1\) amoebas arranged in the grid. An arrangement may be reached in several different ways but it is only counted once. Let \(D(N)\) be the number of different possible arrangements after \(N\) divisions.

For example, \(D(2) = 3\), \(D(10) = 44499\), \(D(20)=9204559704\) and the last nine digits of \(D(100)\) are \(780166455\).

Find \(D(10\,000)\), enter the last nine digits as your answer.

This problem is taken from Project Euler, Problem 763.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=763. Published Saturday, 4th September 2021, 02:00 pm. Solved by 212 members at time of mirroring.

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