Project Euler Lab - Problem 768

#768 - Chandelier

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A certain type of chandelier contains a circular ring of \(n\) evenly spaced candleholders.
If only one candle is fitted, then the chandelier will be imbalanced. However, if a second identical candle is placed in the opposite candleholder (assuming \(n\) is even) then perfect balance will be achieved and the chandelier will hang level.

Let \(f(n,m)\) be the number of ways of arranging \(m\) identical candles in distinct sockets of a chandelier with \(n\) candleholders such that the chandelier is perfectly balanced.

For example, \(f(4, 2) = 2\): assuming the chandelier's four candleholders are aligned with the compass points, the two valid arrangements are "North & South" and "East & West". Note that these are considered to be different arrangements even though they are related by rotation.

You are given that \(f(12,4) = 15\) and \(f(36, 6) = 876\).

Find \(f(360, 20)\).

This problem is taken from Project Euler, Problem 768.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=768. Published Sunday, 17th October 2021, 05:00 am. Solved by 247 members at time of mirroring.

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Mathematical Foundation. Exact counting underlies discrete pricing lattices, scenario enumeration, and combinatorial probability (Phase 7).

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