Project Euler Lab - Problem 789

#789 - Minimal Pairing Modulo $p$

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Given an odd prime \(p\), put the numbers \(1,...,p-1\) into \(\frac{p-1}{2}\) pairs such that each number appears exactly once. Each pair \((a,b)\) has a cost of \(ab \bmod p\). For example, if \(p=5\) the pair \((3,4)\) has a cost of \(12 \bmod 5 = 2\).

The total cost of a pairing is the sum of the costs of its pairs. We say that such pairing is optimal if its total cost is minimal for that \(p\).

For example, if \(p = 5\), then there is a unique optimal pairing: \((1, 2), (3, 4)\), with total cost of \(2 + 2 = 4\).

The cost product of a pairing is the product of the costs of its pairs. For example, the cost product of the optimal pairing for \(p = 5\) is \(2 \cdot 2 = 4\).

It turns out that all optimal pairings for \(p = 2\,000\,000\,011\) have the same cost product.

Find the value of this product.

This problem is taken from Project Euler, Problem 789.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=789. Published Saturday, 12th March 2022, 07:00 pm. Solved by 249 members at time of mirroring.

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Algorithmic Development. Optimal substructure and state-space reasoning are exactly how American-option pricing and optimal execution are solved (Phases 13, 16).

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