Project Euler Lab - Problem 819

#819 - Iterative Sampling

● AdvancedOfficial difficulty: 54%RandomnessTier C - reduced scale in browser; full scale in notebookNot viewed
↖ Euler Lab

Given an \(n\)-tuple of numbers another \(n\)-tuple is created where each element of the new \(n\)-tuple is chosen randomly from the numbers in the previous \(n\)-tuple. For example, given \((2,2,3)\) the probability that \(2\) occurs in the first position in the next 3-tuple is \(2/3\). The probability of getting all \(2\)'s would be \(8/27\) while the probability of getting the same 3-tuple (in any order) would be \(4/9\).

Let \(E(n)\) be the expected number of steps starting with \((1,2,\ldots,n)\) and ending with all numbers being the same.

You are given \(E(3) = 27/7\) and \(E(5) = 468125/60701 \approx 7.711982\) rounded to 6 digits after the decimal place.

Find \(E(10^3)\). Give the answer rounded to 6 digits after the decimal place.

This problem is taken from Project Euler, Problem 819.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=819. Published Saturday, 3rd December 2022, 01:00 pm. Solved by 280 members at time of mirroring.

Why this is useful

Direct Quant. Markov/absorbing-state and simulation reasoning is exactly the machinery behind pricing, risk, and execution models (Phases 7, 8, 13).

We classify relevance honestly - not every Euler problem is a trading application.

Learning mode

Pick how much scaffolding you want. Your choice is remembered per problem.

Scratchpad

Mathematical notes, formulas, pseudocode, hypotheses, complexity notes. Saved automatically with your progress.

Python workbench

Tier C - reduced scale in browser; full scale in notebook
Browser runs a reduced, clearly-labelled educational scale; the original scale is provided in a local notebook.

Real Python (Pyodide) in a sandboxed Web Worker - no network, no filesystem, no DOM access. Ctrl/Cmd+Enter runs. Escape leaves the editor. Stop terminates the worker.

Python runtime not loaded (it boots on first run - a one-time local load).

Check your answer

Answers are checked against a salted hash held in a separate file - not printed in this page. This prevents accidental spoilers; it is not cryptographic protection (see the build notes).

Progressive hints

Confidence

Low confidence schedules this problem for spaced review, even if you solved it.

Reference solution

Spoiler
The complete original explanation (interpretation, naive approach, insight, proof, complexity, Python implementation, tests, common mistakes, alternatives) is hidden and lazy-loaded. Reveal it only after a meaningful attempt - the struggle is where the learning happens.