Project Euler Lab - Problem 95

#95 - Amicable Chains

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The proper divisors of a number are all the divisors excluding the number itself. For example, the proper divisors of \(28\) are \(1\), \(2\), \(4\), \(7\), and \(14\). As the sum of these divisors is equal to \(28\), we call it a perfect number.

Interestingly the sum of the proper divisors of \(220\) is \(284\) and the sum of the proper divisors of \(284\) is \(220\), forming a chain of two numbers. For this reason, \(220\) and \(284\) are called an amicable pair.

Perhaps less well known are longer chains. For example, starting with \(12496\), we form a chain of five numbers: \[12496 \to 14288 \to 15472 \to 14536 \to 14264 (\to 12496 \to \cdots)\]

Since this chain returns to its starting point, it is called an amicable chain.

Find the smallest member of the longest amicable chain with no element exceeding one million.

This problem is taken from Project Euler, Problem 95.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=95. Published Friday, 13th May 2005, 06:00 pm. Solved by 16,784 members at time of mirroring.

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