Project Euler Lab - Problem 967

#967 - $B$-Trivisible Numbers

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A positive integer \(n\) is considered \(B\)-trivisible if the sum of all different prime factors of \(n\) which are not larger than \(B\) is divisible by \(3\).

For example, \(175 = 5^2 \cdot 7\) is \(10\)-trivisible because \(5 + 7 = 12\) which is divisible by \(3\). Similarly, \(175\) is \(4\)-trivisible because all primes dividing \(175\) are larger than \(4\), and the empty summation \(0\) is divisible by \(3\).
On the other hand, \(175\) is not \(6\)-trivisible because the sum of relevant primes is \(5\) which is not divisible by \(3\).

Let \(F(N, B)\) be the number of \(B\)-trivisible integers not larger than \(N\).

For example, \(F(10, 4) = 5\), the \(4\)-trivisible numbers being \(1,3,5,7,9\).
You are also given \(F(10, 10) = 3\) and \(F(100, 10) = 41\).

Find \(F(10^{18}, 120)\).

This problem is taken from Project Euler, Problem 967.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=967. Published Saturday, 1st November 2025, 10:00 pm. Solved by 239 members at time of mirroring.

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