Phase 15 - Lesson 15.2

Implied Volatility and the Volatility Smile/Skew

Why one Black–Scholes number cannot fit every strike, and what the resulting curve tells you about the market’s view of tails.

⏱ 50 min● Advanced🔗 Prereqs: 15.1
↖ Phase 15 hub
Builds on: 15.1 assumed a single constant σ; the market’s prices contradict it.
Leads to: 15.3–15.5 build models (local vol, stochastic vol) that reproduce the smile.

Learning Objectives

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Key Vocabulary

Implied volatility
The value of \(\sigma\) that makes the Black–Scholes price equal the observed market price of an option.
Volatility smile
Implied vol plotted against strike/moneyness that is higher for OTM puts and calls than ATM - a U shape.
Volatility skew
An asymmetric smile (equities): implied vol rises for low strikes (OTM puts), reflecting crash fear.
Moneyness
A normalized strike, e.g. \(K/S\), \(\ln(K/S)\), or \(\ln(K/F)/(\sigma\sqrt{T})\) (standardized).
Risk-neutral density
The pricing distribution \(q(S_T)\) implied by option prices; recovered via Breeden–Litzenberger.
Vega
\(\partial C/\partial\sigma\gt 0\): because price is strictly increasing in \(\sigma\), implied vol is unique when it exists.
Newton–Raphson
A root-finder \(\sigma_{n+1}=\sigma_n-(C(\sigma_n)-C_{mkt})/\text{vega}(\sigma_n)\) exploiting the known derivative.

Intuition & Motivation

Intuition
Implied volatility is not a forecast - it is a change of variables. Because the Black–Scholes call price is a smooth, strictly increasing function of \(\sigma\), any market price can be quoted as the unique \(\sigma\) that reproduces it. Traders quote in vol because it is more stable and comparable across strikes than raw premium. The catch: if the world were truly Black–Scholes, that number would be the same for every strike and maturity. It is not. Plot implied vol against strike and you get a smile or a skew - a direct, model-free fingerprint of the market’s belief that big moves (especially crashes) are far more likely than a lognormal allows.

Definition: inverting the formula

Given a market price \(C_{\text{mkt}}\) for a call at strike \(K\), maturity \(T\), the implied volatility \(\sigma_{\text{imp}}(K,T)\) is the solution of

\[C_{\text{BS}}\big(S,K,r,\sigma_{\text{imp}},T\big)=C_{\text{mkt}}(K,T).\] (15.5)

Because \(\partial C_{\text{BS}}/\partial\sigma=\text{vega}\gt 0\) for \(T\gt 0\), the map \(\sigma\mapsto C_{\text{BS}}\) is strictly increasing, so the solution is unique whenever the price is between its no-arbitrage bounds. This is what makes implied vol a legitimate quoting convention.

Why one σ cannot fit all strikes

Suppose you calibrate a single \(\sigma\) to the ATM option. Black–Scholes then predicts the prices of all other strikes via the same lognormal density. Empirically those predictions are wrong: OTM puts trade richer (higher implied vol) than the ATM number, and OTM calls often do too. If a single \(\sigma\) fit every strike, the implied-vol curve would be flat. It is not - therefore no single constant volatility reproduces the market, and the deviation is the smile.

Key Idea
The smile is a statement about the tails. Higher implied vol for OTM strikes means the market prices those options as if the risk-neutral density has fatter tails than the lognormal. The pattern is model-free: it comes straight from prices, before any model is chosen.

Smile versus skew, and the implied density

The shape carries information. By Breeden–Litzenberger the risk-neutral density is the second strike-derivative of the call price,

\[q(K)=e^{rT}\frac{\partial^2 C}{\partial K^2}\bigg|_{T},\] (15.6)

so the curvature of the price curve (hence the smile) is the density itself, which must be non-negative. Two canonical shapes:

MarketTypical shapeWhat it encodes
FX (symmetric)Smile (U-shaped)Fat tails on both sides; up and down moves both feared
Equity indexSkew (down-sloping)Rich OTM puts: crash fear, negative spot–vol correlation
Short-datedSteeperTails dominate; jump risk large relative to diffusion
Long-datedFlatterAverages out toward a central vol level
Worked Example - Reading a skew: why OTM puts are ‘expensive’
1
An equity index shows implied vol of \(18\%\) ATM but \(26\%\) for a \(10\%\) OTM put.
2
In Black–Scholes terms the put is priced with a much higher \(\sigma\), so it is far more valuable than a flat-vol model says.
3
Model-free reading (15.6): the left tail of the risk-neutral density is fatter than lognormal - the market assigns extra probability to large drops.
4
Economic reading: investors pay up for crash protection; there is a negative correlation between spot and volatility (vol spikes when markets fall).

Interactive: solve for implied volatility (Newton–Raphson)

Vega is the derivative we need, so Newton’s method converges quadratically from a sensible start. Implement the solver and confirm it recovers the \(\sigma\) that generated a price.

Common Mistakes to Avoid
  • Calling implied vol a forecast of future realized vol: it is a risk-neutral quoting device that also embeds risk premia.
  • Comparing raw option premiums across strikes instead of implied vols - premiums confound moneyness with vol.
  • Running naked Newton for deep ITM/OTM options where vega → 0: the update explodes. Bracket with bisection.
  • Expecting a flat line: a non-flat smile is the normal state of the world, not a data error.
Quant Practitioner Tips
  • Quote and interpolate in vol space, not price space - vol is far smoother across strikes and time.
  • Use log-moneyness \(k=\ln(K/F)\) or a standardized \(k/(\sigma\sqrt{T})\) on the x-axis so smiles are comparable across maturities.
  • Seed the solver with a good guess (Brenner–Subrahmanyam ATM approximation) to speed convergence and avoid the flat-vega tails.
  • Watch the ATM skew slope \(\partial\sigma_{imp}/\partial k\): it is the single most-quoted risk-reversal signal.

Knowledge Check

Q1 Easy
Implied volatility is best described as:
The market’s forecast of realized volatility
The \(\sigma\) that makes the Black–Scholes price equal the market price
The historical standard deviation of returns
A number that is the same for all strikes
Q2 Medium
The existence of a non-flat volatility smile directly implies that:
Black–Scholes has an arithmetic error
A single constant \(\sigma\) cannot reproduce all option prices simultaneously
Options are mispriced and arbitrageable
Vega is negative for some strikes
Q3 Medium
An equity index shows implied vol rising sharply for low strikes (OTM puts). Via Breeden–Litzenberger this indicates:
A thinner left tail than lognormal
A fatter left tail: extra risk-neutral probability of large downward moves
That vega is zero ATM
That the risk-free rate is negative

Practical Exercise

You observe three one-year calls on a \(100\)-spot index (\(r=2\%\)): the \(90\)-strike implies \(24\%\), the \(100\)-strike implies \(20\%\), and the \(110\)-strike implies \(19\%\). (a) Sketch and name the shape. (b) What does it say about the risk-neutral density versus lognormal? (c) A colleague proposes pricing all three with the single ATM \(20\%\). What goes wrong, and for which option is the error worst?

▶ Show full solution

(a) Implied vol falls as strike rises (24% → 20% → 19%): a down-sloping skew, the classic equity-index shape.

(b) The high implied vol at the low strike means the market prices the \(90\)-strike put/call region as if large downward moves are more likely than lognormal - a fat left tail. The density is left-skewed relative to the Black–Scholes lognormal.

(c) Using a flat \(20\%\) would under-price the \(90\)-strike (true implied \(24\%\gt 20\%\)) - the worst error, because the skew is steepest there and the market demands a premium for downside protection - and slightly over-price the \(110\)-strike (true \(19\%\lt 20\%\)). A single \(\sigma\) cannot match the cross-section; you need a smile-consistent model (local or stochastic vol).

After the reveal, answer for yourself: If you had to hedge the 90-strike short with the flat-vol delta, would you be over- or under-hedged?

Lesson Summary

Implied volatility is the unique \(\sigma\) that inverts Black–Scholes to a market price; because vega is positive the inversion is well posed. Plotting it against strike reveals a smile (symmetric, FX) or skew (equity), and its very non-flatness proves a single constant volatility cannot price the cross-section. By Breeden–Litzenberger the shape maps directly to the tails of the risk-neutral density, motivating the local- and stochastic-volatility models that follow. A Newton–Raphson solver using vega inverts prices to vols quickly.

Formula Sheet Additions

Implied vol
\[C_{\text{BS}}(S,K,r,\sigma_{\text{imp}},T)=C_{\text{mkt}}(K,T)\]
Unique because vega \(\gt 0\); solved by Newton using the vega slope.
Breeden–Litzenberger
\[q(K)=e^{rT}\,\partial^2 C/\partial K^2\]
Smile curvature is the risk-neutral density; must stay non-negative (no butterfly arbitrage).
Error Log Checklist
  • Did I invert in vol space, not compare raw premiums?
  • Did I guard Newton against vega→0 in the deep tails?
  • Did I read smile height as a tail statement, not a pricing error?
  • Did I keep risk-neutral and physical interpretations distinct?

Retrieval Practice

Close the lesson and answer from memory before checking. This is deliberate, effortful recall - the single highest-yield study action.

▶ Show retrieval prompts & answers
Q: Why is implied volatility uniquely defined for a given option price?
A: Because the Black–Scholes price is strictly increasing in \(\sigma\) (vega \(\gt 0\)); the monotone map has a unique inverse whenever the price sits inside its no-arbitrage bounds.
Q: State in one sentence why a single Black–Scholes \(\sigma\) cannot fit all strikes.
A: Market prices imply different \(\sigma\) at different strikes (a non-flat smile/skew), which a single lognormal density with one \(\sigma\) cannot reproduce.
Q: How does the shape of the smile relate to the risk-neutral density?
A: Via \(q(K)=e^{rT}\partial^2C/\partial K^2\): higher implied vol at a strike fattens the density’s tail there; equity skew means a fat left (downside) tail.

Flashcards

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Implied volatility
The unique \(\sigma\) inverting Black–Scholes to the market price; a quoting convention, not a forecast.
Smile vs skew
Smile = symmetric U (FX, fat both tails); skew = down-sloping (equities, fat left tail / crash fear).
Why the smile exists
One constant \(\sigma\) can’t fit all strikes; non-flat implied vol reveals non-lognormal tails.

Completion Checklist

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Source References

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