Phase 8 - Lesson 8.3

Brownian Motion: Construction and Defining Properties

The continuous-time limit of the random walk: its four defining axioms, existence, the Gaussian marginal structure, and why the paths are continuous.

⏱ 55 min● Advanced🔗 Prereqs: 8.2, 7.6
↖ Phase 8 hub
Builds on: 8.2 rescaled the random walk; 7.6 gave the CLT that produces its Gaussian marginals.
Leads to: Its quadratic variation (8.4) and Gaussian structure (8.5) underpin the Ito calculus of Phase 9.

Learning Objectives

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Key Vocabulary

Brownian motion
A process \((B_t)_{t\ge0}\) with \(B_0=0\), independent stationary Gaussian increments, and continuous paths.
Independent increments
For \(t_0\lt \cdots\lt t_k\), the increments \(B_{t_{i}}-B_{t_{i-1}}\) are mutually independent.
Stationary increments
\(B_{t}-B_{s}\sim\Normal(0,t-s)\) depends only on the gap \(t-s\).
Covariance function
\(\Cov(B_s,B_t)=\min(s,t)\).
Donsker’s theorem
The rescaled random walk \(S_{\lfloor nt\rfloor}/\sqrt n\) converges in distribution to Brownian motion.
Wiener process
Synonym for standard Brownian motion; the measure it induces on path space is Wiener measure.

Intuition & Motivation

Intuition
Brownian motion is what the random walk becomes when you take infinitely many, infinitely small steps. Shrink each step to \(\pm\sqrt{\Delta t}\) and take \(\Delta t\to0\): the CLT turns each increment Gaussian, independence survives, and the jagged path becomes continuous. The result is the canonical continuous-time process - the diffusion at the heart of every option-pricing model. Its four axioms are deceptively simple, yet they force a startling paradox: the paths are continuous everywhere but differentiable nowhere. There is no velocity, only variance; you cannot ask ‘how fast’, only ‘how spread out’. That is precisely why ordinary calculus fails and Ito’s calculus is needed.

Definition and existence

Definition - Standard Brownian motion
A stochastic process \((B_t)_{t\ge0}\) is a standard Brownian motion if: (1) \(B_0=0\); (2) it has independent increments; (3) for \(s\lt t\), \(B_t-B_s\sim\Normal(0,t-s)\) (stationary, Gaussian); (4) \(t\mapsto B_t\) is continuous almost surely.

Existence is not obvious - one must build a process with all four properties simultaneously. Two standard constructions: the Levy-Ciesielski series using a Schauder/Haar basis (guaranteeing continuity), and Donsker’s invariance principle, which realizes BM as the scaling limit of the random walk.

Theorem - Donsker’s invariance principle (idea)
Let \(S_n\) be a random walk with mean-zero, unit-variance increments. The linearly interpolated, rescaled path
\[W^{(n)}_t=\frac{S_{\lfloor nt\rfloor}}{\sqrt n}\ \Longrightarrow\ B_t\quad(n\to\infty),\] (8.4)
converges in distribution (on path space) to Brownian motion. The CLT gives the Gaussian marginals; the diffusive \(\sqrt n\) scale gives the right variance growth.

Moment and covariance structure

From the axioms, for \(s\le t\):

\[\E[B_t]=0,\quad \Var(B_t)=t,\quad \Cov(B_s,B_t)=\min(s,t).\] (8.5)

The covariance follows by writing \(B_t=B_s+(B_t-B_s)\) and using independence: \(\Cov(B_s,B_t)=\Var(B_s)+\Cov(B_s,B_t-B_s)=s+0=s=\min(s,t)\). Because all finite collections \((B_{t_1},\dots,B_{t_k})\) are jointly Gaussian, this mean-zero, \(\min(s,t)\)-covariance structure characterizes BM completely (it is a Gaussian process - see 8.5).

Path regularity: continuous but nowhere differentiable

Property (4) makes the paths continuous. Yet the increment over \([t,t+h]\) has size of order \(\sqrt h\), so the difference quotient \((B_{t+h}-B_t)/h\) is of order \(1/\sqrt h\to\infty\). Formally:

Theorem - Non-differentiability (Paley-Wiener-Zygmund)
With probability 1, the Brownian path \(t\mapsto B_t\) is nowhere differentiable and has infinite variation on every interval.

This is the geometric origin of the whole theory: a path that wiggles so violently that it has no slope but does have a well-defined quadratic variation. The next lesson makes that precise.

Worked Example - Compute a conditional forecast and its variance
1
Question: given \(B_1=0.4\), what is the distribution of \(B_3\)?
2
Decompose \(B_3=B_1+(B_3-B_1)\). The increment \(B_3-B_1\sim\Normal(0,3-1)=\Normal(0,2)\) and is independent of \(B_1\).
3
So conditional on \(B_1=0.4\): \(B_3\sim\Normal(0.4,\,2)\) - mean equals the last value (martingale), variance equals the elapsed time.
4
Best forecast \(\E[B_3\mid\F_1]=B_1=0.4\); forecast standard deviation \(\sqrt2\approx1.414\).
5
This martingale-plus-\(\sqrt{\text{time}}\)-uncertainty structure is exactly how a driftless price is projected forward.

Interactive: generate and inspect Brownian paths

Common Mistakes to Avoid
  • Writing \(\Var(B_t)=t^2\) or \(\sigma t\); for standard BM \(\Var(B_t)=t\), standard deviation \(\sqrt t\).
  • Assuming \(dB_t/dt\) exists - it does not; BM has no derivative, which is why we use stochastic, not ordinary, calculus.
  • Using \(\Cov(B_s,B_t)=st\); the correct covariance is \(\min(s,t)\).
  • Treating overlapping increments as independent; only non-overlapping increments are independent.
Quant Practitioner Tips
  • Remember the trio: mean 0, variance \(t\), covariance \(\min(s,t)\) - they define BM up to its Gaussian law.
  • Model a driftless log-price as \(\sigma B_t\): variance \(\sigma^2 t\), the source of the \(\sigma\sqrt t\) in Black-Scholes.
  • When a computation needs a derivative of \(B\), stop - reach for Ito’s lemma and quadratic variation instead.

Knowledge Check

Q1 Medium
For standard Brownian motion, \(\Cov(B_s,B_t)\) with \(s\le t\) equals:
\(st\)
\(\min(s,t)=s\)
\(t-s\)
\(0\)
Q2 Medium
Brownian sample paths are:
Smooth and differentiable
Continuous everywhere but differentiable nowhere
Discontinuous with jumps
Piecewise linear
Q3 Hard
Donsker’s theorem states that the rescaled random walk \(S_{\lfloor nt\rfloor}/\sqrt n\):
Diverges
Converges in distribution to Brownian motion
Converges to a straight line
Becomes a Poisson process

Practical Exercise

Let \((B_t)\) be standard Brownian motion. (a) Find the distribution of \(B_2-B_5\) is asked incorrectly - instead find the law of \(B_5-B_2\). (b) Compute \(\E[B_2 B_5]\). (c) Are \(B_2\) and \(B_5-B_2\) independent? Use this to recompute (b).

▶ Show full solution

(a) \(B_5-B_2\sim\Normal(0,5-2)=\Normal(0,3)\) by stationary Gaussian increments.

(b) \(\E[B_2 B_5]=\Cov(B_2,B_5)=\min(2,5)=2\) (both mean 0).

(c) Yes: \(B_2\) is a function of increments up to time 2, and \(B_5-B_2\) is the increment on \((2,5]\); non-overlapping increments are independent. Then \(\E[B_2 B_5]=\E[B_2(B_2+(B_5-B_2))]=\E[B_2^2]+\E[B_2]\E[B_5-B_2]=2+0=2\), matching (b).

After the reveal, answer for yourself: Why does the answer \(\min(s,t)\) equal the variance of the earlier time?

Lesson Summary

Brownian motion is the continuous-time scaling limit of the random walk, defined by four axioms: start at 0, independent and stationary Gaussian increments \(B_t-B_s\sim\Normal(0,t-s)\), and continuous paths. Its structure is fixed by mean 0, variance \(t\), and covariance \(\min(s,t)\). The paths are continuous everywhere but differentiable nowhere - the paradox that forces stochastic calculus.

Formula Sheet Additions

BM moments
\[\E[B_t]=0,\ \Var(B_t)=t,\ \Cov(B_s,B_t)=\min(s,t)\]
The defining second-order structure.
Increment law
\[B_t-B_s\sim\Normal(0,t-s),\ \text{independent of }\F_s\]
Independent stationary Gaussian increments.
Error Log Checklist
  • Did I use \(\Var(B_t)=t\) (not \(t^2\) or \(\sigma t\))?
  • Did I use \(\Cov=\min(s,t)\), and only treat non-overlapping increments as independent?
  • Did I resist differentiating \(B\)?

Retrieval Practice

Close the lesson and answer from memory before checking. This is deliberate, effortful recall - the single highest-yield study action.

▶ Show retrieval prompts & answers
Q: List the four defining properties of standard Brownian motion.
A: \(B_0=0\); independent increments; \(B_t-B_s\sim\Normal(0,t-s)\) (stationary Gaussian); almost-surely continuous paths.
Q: Give \(\E[B_t]\), \(\Var(B_t)\), and \(\Cov(B_s,B_t)\).
A: 0, \(t\), and \(\min(s,t)\).
Q: Why are Brownian paths not differentiable?
A: Increments scale like \(\sqrt h\), so difference quotients \((B_{t+h}-B_t)/h\sim1/\sqrt h\to\infty\); no slope exists.

Flashcards

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Brownian covariance
\(\Cov(B_s,B_t)=\min(s,t)\); mean 0, variance \(t\).
Path regularity
Continuous everywhere, differentiable nowhere, infinite variation.

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