Cumulative Assessment

Cumulative II - Analysis, Probability & Stochastics (Phases 5–9)

25 interleaved questions spanning multiple phases. Cumulative review is one of the most powerful retention tools - it forces retrieval of older material right when it is starting to fade.

Q1 Medium
\(\int_0^T W_s\,dW_s\) equals:
\(\tfrac12 W_T^2\)
\(\tfrac12 W_T^2-\tfrac12 T\)
\(W_T^2-T\)
\(\tfrac12 W_T^2+\tfrac12 T\)
Q2 Easy
In the Itô multiplication table, \((dW)^2\) equals:
\(0\)
\(dt\)
\(dW\)
\((dt)^2\)
Q3 Medium
Brownian sample paths are:
Smooth and differentiable
Continuous everywhere but differentiable nowhere
Discontinuous with jumps
Piecewise linear
Q4 Easy
A failed Cholesky (a non-positive radicand) on an estimated covariance most likely means:
The code has a bug for sure
The matrix is not positive definite - often too few samples or a bad estimate
The matrix is too large
You must switch to LU
Q5 Easy
In \(PA=LU\) with partial pivoting, the matrix \(L\) is:
Upper-triangular with unit diagonal
Unit lower-triangular with entries \(|\ell_{ik}|\le1\)
Orthogonal
Diagonal
Q6 Easy
For the simple symmetric random walk, \(\mathrm{sd}(S_n)\) grows like:
\(n\)
\(\sqrt n\)
\(\log n\)
constant
Q7 Medium
Fubini’s theorem (as opposed to Tonelli) additionally requires:
\(f\ge0\)
\(f\in L^1(\mu\times\nu)\)
A finite measure space
Continuity of \(f\)
Q8 Hard
Which property guarantees the n-step matrix \(P^n\) actually converges (not just that \(\pi\) exists)?
Recurrence alone
Aperiodicity (together with irreducibility)
A symmetric \(P\)
Having two states
Q9 Medium
For standard Brownian motion, \(\Cov(B_s,B_t)\) with \(s\le t\) equals:
\(st\)
\(\min(s,t)=s\)
\(t-s\)
\(0\)
Q10 Medium
The single algorithmic difference between classical and modified Gram-Schmidt is:
MGS normalizes twice
MGS subtracts projections against the running, partially-orthogonalized vector rather than the original column
MGS uses a different \(R\)
MGS requires pivoting
Q11 Medium
Countable additivity of a measure directly implies all of the following EXCEPT:
Monotonicity
Continuity from below
That every set is measurable
Countable subadditivity
Q12 Medium
Least squares via \(Rx=Q^\top b\) is preferred over the normal equations mainly because:
It uses fewer flops
It keeps the conditioning at \(\kappa(A)\) instead of \(\kappa(A)^2\)
It works for singular \(A\)
It avoids computing \(Q\)
Q13 Hard
The characteristic-function proof of the CLT works because \(\phi_Y(t/\sqrt n)^n\to\):
\(e^{-t^2/2}\)
\(e^{-|t|}\)
\(1\)
\(e^{it}\)
Q14 Medium
To draw \(X\sim\Normal(0,\Sigma)\) from standard normals \(Z\) with \(\Sigma=LL^\top\), set:
\(X=\Sigma Z\)
\(X=LZ\)
\(X=L^{-1}Z\)
\(X=Z/L\)
Q15 Medium
A Gaussian process is completely determined by:
Its sample paths
Its mean function and covariance function
Its maximum over time
Its first four moments
Q16 Easy
In Euler–Maruyama, the noise increment is:
\(\sigma S\,\Delta t\,Z\)
\(\sigma S\,\sqrt{\Delta t}\,Z\)
\(\sigma S\,Z\)
\(\sigma S\,(\Delta t)^2 Z\)
Q17 Medium
The stationary distribution \(\pi\) of a chain with transition matrix \(P\) satisfies:
\(P\pi=\pi\)
\(\pi P=\pi\) with \(\sum_i\pi_i=1\)
\(\pi P=0\)
\(P^2=P\)
Q18 Easy
Markov’s inequality \(\Prob(X\ge a)\le\E[X]/a\) requires which assumption?
\(X\) is normal
\(X\ge 0\)
\(X\) has finite variance
\(X\) is discrete
Q19 Easy
The essential difference between the Lebesgue and Riemann integrals is that Lebesgue:
Partitions the range (y-axis) and weights level sets by measure
Partitions the domain into finer subintervals
Only works for continuous functions
Always gives a larger value
Q20 Hard
The martingale-transform theorem implies that a predictable betting strategy on a fair game yields wealth with:
Positive expected gain
Zero expected gain (still a martingale)
Negative expected gain
Undefined expectation
Q21 Medium
A continuous function on a compact set is guaranteed to:
Be differentiable
Attain its maximum and minimum
Be linear
Have no zeros
Q22 Medium
The Cantor set is an example of a set that is:
Countable and of positive measure
Uncountable and of measure zero
Finite
Non-measurable
Q23 Medium
Which random time is a stopping time with respect to the natural filtration of a price process?
The time of the global maximum over all n
The first time the price reaches 120
The time two steps before the crash
The last time before a peak
Q24 Medium
Hölder’s inequality at \(p=q=2\) specializes to:
Minkowski’s inequality
The triangle inequality
Cauchy–Schwarz
Jensen’s inequality
Q25 Easy
For a martingale \((M_n)\), \(\E[M_{n+1}\mid\F_n]\) equals:
\(M_0\)
\(M_n\)
\(\E[M_n]\)
\(0\)
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