Phase 1 Exam

Mathematical Language & Proof - Phase Exam

15 interleaved questions drawn from every lesson in this phase. Interleaving mixes topics on purpose - that difficulty is what builds durable, transferable understanding. Aim for 70%+ before advancing; below that, revisit the flagged lessons.

How this exam teaches
Questions are shuffled across lessons (not blocked by topic) so you practice choosing the right idea. Missed questions are added to your review queue automatically.
Q1 Medium
Which statement about the function f: ℝ→ℝ, f(x)=x² is correct?
It is injective
It is surjective onto ℝ
It is neither injective nor surjective onto ℝ
It is a bijection
Q2 Medium
‘A function is integrable only if it is bounded (on a closed interval).’ This tells us:
boundedness is sufficient for integrability
boundedness is necessary for integrability
integrability is sufficient for boundedness
boundedness and integrability are equivalent
Q3 Easy
To disprove the universal claim ‘every continuous function is differentiable’, the correct move is:
a proof by contradiction
a proof by contrapositive
exhibit one counterexample such as |x| at 0
a direct proof
Q4 Easy
An induction argument with a correct inductive step but NO verified base case proves:
the statement for all n
the statement for no n in general
only the base case
the contrapositive
Q5 Medium
In the definition ‘∀ε>0 ∃N: n≥N ⇒ |a_n−L|<ε’, the threshold N is allowed to depend on:
n
ε only
both n and ε
nothing
Q6 Easy
To prove A = B for two sets, the standard method is to show:
A ⊆ B only
B ⊆ A only
both A ⊆ B and B ⊆ A
that A and B have the same number of elements
Q7 Easy
The contrapositive of ‘if n² is even then n is even’ is:
if n is even then n² is even
if n is odd then n² is odd
if n² is odd then n is odd
if n is not even then n² is even
Q8 Medium
Proof by contradiction of a statement S proceeds by:
assuming S and deriving S again
assuming ¬S and deriving a logical impossibility
assuming the hypothesis and reaching the conclusion
checking finitely many cases
Q9 Medium
Strong induction differs from weak induction in that the inductive hypothesis assumes:
only P(k)
P(k+1) directly
P(j) for all j from the base up to k
nothing
Q10 Medium
Which sequence converges by the Monotone Convergence Theorem?
a_n=(−1)^n
a_n=n
a_n=1−1/n
a_n=sin n
Q11 Medium
A relation that is reflexive, symmetric, and transitive necessarily produces:
a total order
a partition of the set into disjoint classes
a bijection
a Cartesian product
Q12 Hard
Negate: ‘∀ε>0 ∃δ>0 such that P(ε,δ)’.
∀ε>0 ∀δ>0, ¬P
∃ε>0 ∀δ>0, ¬P
∃ε>0 ∃δ>0, ¬P
∀ε>0 ∃δ>0, ¬P
Q13 Medium
Which statement is most naturally attacked by contrapositive?
√2 is irrational
if n² is odd then n is odd
there are infinitely many primes
the empty set is a subset of every set
Q14 Medium
For proving every integer n≥2 has a prime factorization, the natural technique is:
weak induction
strong induction
a single counterexample
direct computation only
Q15 Hard
To prove 1/n² → 0, choosing N works if for n≥N we get 1/n²<ε. A valid choice of N is any integer greater than:
ε
1/ε
1/√ε
√ε
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