Phase 10 Exam

Convex Optimization & Numerical Methods - Phase Exam

15 interleaved questions drawn from every lesson in this phase. Interleaving mixes topics on purpose - that difficulty is what builds durable, transferable understanding. Aim for 70%+ before advancing; below that, revisit the flagged lessons.

How this exam teaches
Questions are shuffled across lessons (not blocked by topic) so you practice choosing the right idea. Missed questions are added to your review queue automatically.
Q1 Easy
A set \(C\) is convex iff:
It is bounded
For any \(x,y\in C\), the segment \([x,y]\subseteq C\)
It contains the origin
It is closed
Q2 Easy
For a convex optimization problem, a local minimum is:
Possibly not global
Always also a global minimum
Never unique
A saddle point
Q3 Medium
Weak duality states that for \(\lambda\ge0\):
\(g(\lambda,\nu)\ge p^\star\)
\(g(\lambda,\nu)\le p^\star\)
\(g=p^\star\) always
\(d^\star\gt p^\star\)
Q4 Medium
For a strongly convex \(f\), gradient descent with a suitable fixed step converges:
Sublinearly
Linearly, at rate depending on \(\kappa=L/\mu\)
Quadratically
Not at all
Q5 Medium
The minimum-variance portfolio weights (fully invested) are:
\(\Sigma^{-1}\mu\)
\(\Sigma^{-1}\mathbf1/(\mathbf1^\top\Sigma^{-1}\mathbf1)\)
\(\mathbf1/n\)
\(\Sigma\mathbf1\)
Q6 Medium
The second-order condition for convexity of twice-differentiable \(f\) is:
\(\nabla f(x)=0\)
\(\nabla^2 f(x)\succeq0\) everywhere
\(\nabla^2 f(x)\preceq0\)
\(f(x)\ge0\)
Q7 Medium
The first-order optimality condition over a convex feasible set \(C\) is:
\(\nabla f_0(x^\star)=0\) always
\(\nabla f_0(x^\star)^\top(y-x^\star)\ge0\ \forall y\in C\)
\(f_0(x^\star)=0\)
\(\nabla^2 f_0\succ0\)
Q8 Medium
Which condition guarantees strong duality for a convex problem?
The objective is bounded
Slater's condition (a strictly feasible point exists)
All constraints are equalities
The Hessian is diagonal
Q9 Medium
Newton's method on a strictly convex QUADRATIC converges in:
Infinitely many steps
One step
Two steps
\(\kappa\) steps
Q10 Medium
Ridge regression differs from OLS by:
Using an \(\ell_1\) penalty
Adding \(\lambda\|\beta\|_2^2\), giving \(\hat\beta=(X^\top X+\lambda I)^{-1}X^\top y\)
Being non-convex
Removing the intercept
Q11 Medium
Which operation can DESTROY convexity?
Adding two convex functions
Taking the pointwise maximum
Multiplying two convex functions
Affine precomposition \(f(Ax+b)\)
Q12 Medium
For \(\min\tfrac12\|x\|_2^2\) s.t. \(a^\top x=1\), the optimum is:
\(a\)
\(a/\|a\|_2^2\)
\(a/\|a\|_2\)
\(0\)
Q13 Medium
Complementary slackness says:
\(\lambda_i^\star=f_i(x^\star)\)
\(\lambda_i^\star f_i(x^\star)=0\)
\(\lambda_i^\star\gt 0\) always
\(f_i(x^\star)=0\) always
Q14 Easy
A large condition number \(\kappa\) primarily makes gradient descent:
Diverge
Zig-zag and converge slowly
Converge quadratically
Ignore the gradient
Q15 Easy
For two assets with equal variances and \(\rho\lt 1\), the minimum-variance weight on asset 1 is:
\(1\)
\(1/2\)
\(0\)
Undefined
← Phase 10 lessons All exams Review missed →