Phase 2 Exam

Single-Variable Calculus - Phase Exam

20 interleaved questions drawn from every lesson in this phase. Interleaving mixes topics on purpose - that difficulty is what builds durable, transferable understanding. Aim for 70%+ before advancing; below that, revisit the flagged lessons.

How this exam teaches
Questions are shuffled across lessons (not blocked by topic) so you practice choosing the right idea. Missed questions are added to your review queue automatically.
Q1 Easy
For lim_{x→c} f(x)=L, the condition 0<|x−c|<δ explicitly excludes x=c because the limit:
requires f(c) to exist
describes the approach to c, independent of the value at c
is always equal to f(c)
only makes sense for continuous f
Q2 Easy
The derivative f′(x) is defined as the limit of:
f(x+h)−f(x)
(f(x+h)−f(x))/h as h→0
(f(x+h)−f(x))/h as x→0
f(x)/x
Q3 Easy
The derivative of sin(x²) is:
cos(x²)
2x cos(x²)
2x sin(x²)
cos(2x)
Q4 Easy
The linear (first-order Taylor) approximation of f about a is:
f(a)
f(a)+f′(a)(x−a)
f′(a)(x−a)
f(a)+f″(a)(x−a)²/2
Q5 Easy
At an interior local maximum of a differentiable function, Fermat’s theorem guarantees:
f″=0
f′=0
f=0
f is increasing
Q6 Easy
FTC Part 1 states that d/dx ∫_a^x f(t)dt equals:
F(x)−F(a)
f(x)
f′(x)
0
Q7 Easy
The geometric series ∑ ar^n converges if and only if:
a≠0
|r|<1
r>0
a<1
Q8 Medium
f(x)=(x²−9)/(x−3) at x=3 has:
a jump discontinuity
a removable discontinuity with limit 6
no limit
an infinite discontinuity
Q9 Medium
Which is TRUE about the relationship between continuity and differentiability?
continuous ⇒ differentiable
differentiable ⇒ continuous
they are equivalent
neither implies the other
Q10 Medium
Differentiating x²+y²=25 implicitly gives 2x+2yy′=0, so y′ equals:
−x/y
x/y
−y/x
−2x
Q11 Medium
In the Maclaurin series e^x=∑ x^k/k!, the coefficient of x³ is:
1
1/3
1/6
3
Q12 Medium
If f′(c)=0 and f″(c)>0, then c is a:
local maximum
local minimum
saddle point
global maximum
Q13 Medium
∫₀¹ (4x³) dx equals:
1
4
x⁴
0
Q14 Medium
Which statement is correct about the harmonic series ∑1/n?
it converges because 1/n→0
it diverges even though 1/n→0
the ratio test proves it converges
it converges to 1
Q15 Medium
The Intermediate Value Theorem lets you conclude x³+x−1 has a root in (0,1) because it is continuous and:
f(0) and f(1) have opposite signs
f is increasing
f is a polynomial
f(0)=f(1)
Q16 Medium
For a balance under continuous compounding, A(t)=A₀e^{rt}. Its instantaneous growth rate A′(t) equals:
r
rA₀
rA(t)
A(t)/r
Q17 Medium
A 13 ft ladder slides down a wall; the base moves out. Which relation should you differentiate w.r.t. t for a related-rates problem?
x+y=13
x²+y²=13²
xy=13
x²−y²=13
Q18 Medium
For a bond, ΔP/P ≈ −DΔy + ½CΔy². The convexity term CΔy² is:
the linear risk
the second-order Taylor curvature correction
always negligible
the same as duration
Q19 Medium
A firm maximizes profit π=R−C. The first-order condition is:
R=C
R′=C′ (marginal revenue = marginal cost)
R′=0
C′=0
Q20 Medium
The present value of a continuous stream c(t) discounted at rate r over [0,T] is:
∫₀ᵀ c(t)dt
∫₀ᵀ c(t)e^{−rt}dt
∫₀ᵀ c(t)e^{rt}dt
c(T)e^{−rT}
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