Project Euler Lab - Problem 588

#588 - Quintinomial Coefficients

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The coefficients in the expansion of \((x+1)^k\) are called binomial coefficients.
Analoguously the coefficients in the expansion of \((x^4+x^3+x^2+x+1)^k\) are called quintinomial coefficients.
(quintus= Latin for fifth).

Consider the expansion of \((x^4+x^3+x^2+x+1)^3\):
\(x^{12}+3x^{11}+6x^{10}+10x^9+15x^8+18x^7+19x^6+18x^5+15x^4+10x^3+6x^2+3x+1\)
As we can see \(7\) out of the \(13\) quintinomial coefficients for \(k=3\) are odd.

Let \(Q(k)\) be the number of odd coefficients in the expansion of \((x^4+x^3+x^2+x+1)^k\).
So \(Q(3)=7\).

You are given \(Q(10)=17\) and \(Q(100)=35\).

Find \(\sum_{k=1}^{18}Q(10^k)\).

This problem is taken from Project Euler, Problem 588.
Problem text © Project Euler, licensed under CC BY-NC-SA 4.0. Original: projecteuler.net/problem=588. Published Sunday, 29th January 2017, 04:00 am. Solved by 531 members at time of mirroring.

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